From ohms law -
Current through battery (I) = V/((R1+R2+R3) = 12/(21+32+31)
Current (I) = 0.143 Amp
submitted, you will be unable to return to this part. Three resistors - R1 = 212,...
Part 1 You have three resistors, R1 = 7,00 32, R2 = 8.00 12, and R3 = 9.00 32, connected as shown in (Figure 2). The terminals of a battery with emf 12.0 V and negligible internal resistance are connected to points a and b. Find the power output of the battery. Express your answer with the appropriate units. Part J Find the power input to Ri. Express your answer with the appropriate units. Part 6 Find the power input...
Three resistors, R1 = 24 Ω , R2 = 69 Ω , and R3=R, are connected in parallel with a 12 V battery. Part A: The total current flowing through the battery is 0.88 A . Find the value of resistance R. Part B: Find the current through each resistor. Part C: If the total current in the battery had been greater than 0.88 A , would your answer to part A have been larger or smaller?
The circuit shown in the figure below contains three resistors (R1, R2, and R3) and three batteries (VA, VB, and Vc). The resistor values are: R1=2 Ohms, R2=R3=4 Ohms, and the battery voltages are Va=25 V, V8=15 V, and Vc=20 V. When the circuit is connected what will be the current through R2? Vc R1 + VB R2 R3 0.75 A 1.25 A 2.5 A 3.0 A 3.75 A
2. Three resistors (R1, R2, and R3) are connected in parallel to a battery with a voltage of V. Assign values to R1 (2.0 Ω), R2 (4.0 Ω), and R3 (6.0 Ω) and voltage (9.0 V) a) Solve for the current through the battery. (3 pts) b) Solve for the current through R2. (3 pts)
Three resistors are connected to an ideal battery (no internal resistance) as shown. The values are: EMF = 19 V R1 = 39 Ohms R2 = 70 Ohms R3 = 66 Ohms What is the total power output by the battery? Hint: You might consider the current through each individual resistor.
The three resistors in the figure are R1 = 25 2, R2 = 50 and R3 = 100 1. a) What is the total resistance of the circuit? b) What are the currents 11, 12 and 13 for a 12V battery E = 12 V R R₂ 12 R3 1
IP Three resistors, R1 = 15 Ω , R2 = 62 Ω , and R3=R, are connected in series with a 24.0 V battery. The total current flowing through the battery is 0.15 A . Find the value of resistance R. Find the potential difference across each resistor.
The circuit shown in the figure below contains three resistors
(R1, R2, and R3) and three batteries (VA, VB, and VC). The resistor
values are: R1=2 Ohms, R2=R3=6 Ohms, and the battery voltages are
VA=25 V, VB=15 V, and VC=20 V. When the circuit is connected, what
will be the power dissipated by R2?
VC R1 + VA VE R2 R3
The circuit shown in the figure below contains three resistors (R1, R2, three batteries (VA, V8, and Vc). The resistor values are: R1-2 Ohms, R2=R3=4 Ohms, and the battery voltages are Va=25 V, VB=15 V, and Vc=20 V. When the circuit is connected what will be the current through R2? VC R1 ** VA ++ VE R2 ho {} R3 0.75 A 1.25 A O 2.5 A O 3.0 A 375 A
The circuit shown in the figure below contains three resistors (R1, R2, and R3) and three batteries (VĄ, VB, and Vc). The resistor values are: R1=2 Ohms, R2=R3=6 Ohms, and the battery voltages are VA=25 V, VB=15 V, and Vc=20 V. When the circuit is connected, what will be the power dissipated by R2? VC HA R1 + VA + VB R2 my R3