Question

The three resistors in the figure are R1 = 25 2, R2 = 50 and R3 = 100 1. a) What is the total resistance of the circuit? b) What are the currents 11, 12 and 13 for a 12V battery E = 12 V R R₂ 12 R3 1

Answer 1

Resistors Rg and Riz are connected in parllel, if Rq3 is their equivalent resistance, then ㅗ 1 Ry + - Rq3 ㅗ R3 ㅗ loo 2+1 =3 + 50 100 100 => Roz= 100 - 33.33.22 3 so we have have to E-12V THE R, b Rg3 Now . resistors Res and R, are connected in series, so their equivalent resistance is R = Rg3+R, 33.33 + 25 => R= 58.33)

Current deliver by the According to ohn's law battery is 'I' (say) Voltage = Resistance x current EE RxI I= E 12 58.33 0. 2057 A Since current flowing must be same, through battery, R, and Raz SO, I= 0.2057A Also, corrent through Raz is I= 0.2057 A voltage accross Rq and Rg combination 80, Rq3 or isi Vat Rq3.XI = 33.33x0.2057 => Vab 6.856 V

whet Rq ie. b a. R3 voltage accross both Rg and R3 is 6.856 V so, current through R2 2 Iar Vab Rg [ohm's low => Iq = 6.856 [o 0.13712 50 Similarly current through 1. Rza བ Iz Vab R3 - 6.856 100 0.06856 A >