Question

#13

c. What volume of .00 M HNO3 is needed to make 675 mL of 0.750 M HNO:? d. What volume of 15,0 M H,PO is needed to make 750.0 mL of 3.0 M H3PO4? 13. A group of shipwreck survivors floated for several days on a life raft before being rescued. Those who had drunk some seawater were found to be suffering the most from dehydration. Explain.

Answer 1

Here, in the given problem we have to ase the formula vosi = V2 S2 ie let vomi of 9.00 (4) HNO is needed to make 675 ml 0.750 (M) HNO3 Si=9.001N) HNO3 V2 = 675 ml HNO3 S2 = 0.750(M) So, we can write - vis, =V2 S2 on, V, 19.00) = 67500.750 vo= 56.25 ml so 56.25 ml 9(M) HNO, nude. (d.). Now, in the secom case, vi = volume of H3PO4 neded of 1.5(M) H3PO4 Si=15(M) V2 = 750 ml S2 = 3(M) So, visi = V282 [ Previously I mentione what is viv2, on VI(15) = 75013 V = 150 ml So, 150 ml of 15(M) H₃PO4 neded. s, and f₂ 7

Sea water contains salt, in a huge amount. But human body can withstand salt till a pasticutan amount - Human kidney can make cosine from that waters which has small amount Day water (unless sea waten which has high & salt pencentage). So, il moro seawaters is dounk then the consumaros have to uosinale- more than the water they doink. Eventually the ship wreck sunuivono consumens of sea bater) would suffer from de hydnalicub.
If you still have any query feel free to ask in the comments and if you like my work please give a thumbs up.