what volume of 5.00X10^-3 M HNO3 is needed to titrate 80.00 mL of 5.00X 10^-3 M...

Question

Question

what volume of 5.00X10^-3 M HNO3 is needed to titrate 80.00 mL of 5.00X 10^-3 M Ca(OH)2 to the equivalence point

Answer 1

Answer #1

The reaction is the following:

2HNO₃ + Ca(OH)₂ -----------> Ca(NO₃)₂ + 2H₂O

With this reaction, we see that it takes 2 moles of HNO₃ to react with 1 mole of Ca(OH)₂ so:

mol A = mol B and in this case:

mole HNO₃ = 2 moles

mole Ca(OH)₂ = 1 mole

mole HNO₃ / mole Ca(OH)₂ = 2/1

mole HNO₃ = 2 mole Ca(OH)₂

If mole = M * V then:

M_aV_a = 2M_bV_b

0.005 * V_a = 2 * 0.005 * 80

V_a = 160 mL

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Answer 2

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