What volume of 0.114 M HCl is needed to titrate 25.0 mL of 0.172 M pyridine (C5H5N) to its equivalence point? For pyridine, pKb = 8.77.
What volume of 0.114 M HCl is needed to titrate 25.0 mL of 0.172 M pyridine...
4. Suppose you titrate 50.00 mL of 1.20 M pyridine, C5H5N, with 0.634 M HCl. (a) How many moles of pyridine are present in the original pyridine solution? (b) What is the initial pH? (c) What volume (in mL) of HCl solution is required to reach the equivalence point? (d) What is the pH at the equivalence point? (e) What is the pH of the solution after the addition of 104 mL of HCl?
4. Suppose you titrate 50.00 mL of 1.20 M pyridine, C5H5N, with 0.634 M HCl. (a) How many moles of pyridine are present in the original pyridine solution? (b) What is the initial pH? (c) What volume (in mL) of HCl solution is required to reach the equivalence point? (d) What is the pH at the equivalence point? (e) What is the pH of the solution after the addition of 104 mL of HCl?
What volume of 0.0850 M HCl is required to titrate 25.00 mL of a 0.100 M NH3 solution to the equivalence point?? Please show work so I can understand -- thank you.
You titrate 25.0 mL of 0.100 M HCl solution with 0.086 M NaOH. What is the limiting reactant?You titrate 25.0 mL of 0.100 M HCl solution with 0.086 M NaOH. What is the final [H3O+]?You titrate 25.0 mL of 0.100 M HCl solution with 0.086 M NaOH. What is the final pH of the solution?
3. How many mL of 0.450 M HCl are needed to titrate 25.0 mL solution of 0.250 M Na2CO3 solution? Na2CO3(aq) + 2HCl(aq) + 2NaCl(aq) + CO2(g) + H2O(l)
What volume (in mL) of 3.75×10^−2 M HNO3 is needed to titrate 45.0 mL of 1.15×10^−2 M LiOH to the equivalence point?
what volume of 5.00X10^-3 M HNO3 is needed to titrate 80.00 mL of 5.00X 10^-3 M Ca(OH)2 to the equivalence point
Consider the titration of 25.00 mL of 0.08364 M pyridine with 0.1067 M HCl (a) What volume of the titrant must be added to reach the equivalence point? (b) Find the pH when 4.63 mL of the titrant has been added.
A titration of 60.0mL of 0.30M pyridine, C5H5N, required 90.0mL of 0.20 M HCl to reach the equivalence point. What is the pH at this equivalence point? Kb(C5H5N) = 2.0x10^-9
24. A 25.0 mL volume of a 0.200 M N,H& solution (K 1.70x10 titrated to the equivalence point with 0.100 M HCl. What is the pH of this solution at the equivalence point? The titration is a. 4.70 b. 8.23 c. 7.00 d. 9.30 24. A 25.0 mL volume of a 0.200 M N,H& solution (K 1.70x10 titrated to the equivalence point with 0.100 M HCl. What is the pH of this solution at the equivalence point? The titration is...