Question

4. Mr. Burnes bought a bottle of vinegar and wondered how concentrated the acetic acid (CH-COOH; mm = 60.05 g/mol) was inside. He titrated it with 0.00182 M NaOH that he found in a general chemistry laboratory. It took 9.90 mL of NaOH to reach the equivalence point. See titration curve on next page. A. What is the concentration of acetic acid if 23.7 mL of vinegar was used for the titration? B. Mr. Burnes bought the economy size bottle that contains 5.53 L of vinegar. How many grams of acetic acid was contained in the new bottle of vinegar? C. Write the complete and net ionic equations for the titration of acetic acid (CH,COOH) with sodium hydroxide (NaOH) to make acetate (CH.COO). D. Write the acid dissociation constant (K) expression for acetic acid using the following equation.

Answer 1

4) acetic Aid CH3COOH CNOO HJ 0OD182 M, 9.Jom 60 Os M N = 0 00l82 y SJo HODNU 0.018018 mmol A) VcHcooH Tr equivalene poivd 23.7 ml nNaoH nCH COOH Mx 23 1 O.018018 O.000760 Ame S S3 Lit (Mxv) Иснзсоон CHCOOH (o oo076 x S53) o. oo42 mol X wCH3CooH=0 0o2 x 60 o5) m = 0.2524gm WCHgCOOM

H2) CH3coONacop) CH3COOH + NaoH (a) Complete ionc eah Nd'co2) + CH3CO Cu) Hco) Nacazoa CHaCOs)Hog) Na+o H204) Net ian ean H2Oa) OH CHSCOU)30a) Ka H20u) CH3CODH (a) CCH3 COOJ CH307 Ka CCH COOH re