Homework Answers
molarity of NaOH = 0.0993 mol/L
Volume of NaOH = 8.40 ml
Number of moles of NaOH = (Molarity / 1000) * 8.40 = (0.0993 mol/L / 1000 ml) * 8.40 ml = 8.34 * 10-4 moles
Number of moles of CH3COOH will be equal to number of moles of NaOH
Number of moles of CH3COOH = 8.34 * 10-4 moles
Molecular weight of CH3COOH = 60.052 g / mol
Mass of CH3COOH = 8.34 * 10-4 moles * 60.052 g / mol = 0.05047
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i need help with questions for part b only please
ZULU Acid-Base Titration (worksheet to be...
A Weak Acid - Strong Base Titration Report Sheet Date: Name: Volume of CH3COOH (ml): Sample...
A Weak Acid - Strong Base Titration Report Sheet Date: Name: Volume of CH3COOH (ml): Sample Code: { 10.00 mL Temperature: _22.0_ Initial Volume of NaOH (mL): 0.00 Molarity of NaOH (from label): _0.1013__ RUN 1 From LabQuest Titration Curve From 1st Derivative From Printed Titration Curve Instructor's Approval of LabQuest Data Volume of NaOH at Equivalence Pt (mL) 12.00mL 12.65mL Average Volume of NaOH at Equivalence Pt Include printed graphs of titration curve and 1st Derivation with Report Sheet...
I need help calculating the mass percent and with the post lab question #2. Part 1...
I need help calculating the mass percent and with the post lab
question #2.
Part 1 Mass Initial | Final Vol Nall Moles concen. KPHCG (ML) I (m2) Used (m2) KHP (mol)/NaOH(M) 0.28470.00 13.60r 13.600 10.00- 0.1025 2 UZ + ZANT 13.600 24.45 1 10.85 0.001128 10.40 Aug NaOH Concentration (M):0.1032 Part2 Vinegar identification # 4 Vinegar sample date: (011/ Vol Vinegat Initial Final Yol NaOH Mol Acotic Mass Acctic Mass % Titr ULST I OML Used (ml) Acid (mol)...
A vinegar titration was completed using a pH meter as an indicator of the changing pH....
A vinegar titration was completed using a pH meter as an indicator of the changing pH. A 25.00 mL sample of diluted vinegar (diluted by a factor of 5) was placed in a beaker and subsequently titrated with 0.1098 M NaOH. A derivative curve of the titration suggested that the equivalence point occurred at 40.90 mL. Calculate the mass percent of CH_3COOH. (The density of vinegar is 1.008 g/mL.) Moles of base at the equivalence point = Moles of acid...
a-c 5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor)...
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
i need all answers Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1...
i
need all answers
Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar (6) Volume of Vinegar (ml) Density - 1.005 g/ml Initial NaOH volume in syringe (ml) Final NaOH volume in syringe (ml) Volume of NaOH delivered (mL) Volume of NaOH delivered (L) Molarity of NaOH Moles of NaOH delivered Reaction of NaOH with Acetic Acid Moles of Acetic Acid in vinegar sample Molar mass of Acetic...
A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar...
A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar needs 45.0 mL of 0.135 M NaOH to reach the equivalence point in a titration CH3COOH(aq)+NaOH(aq)→H2O(l)+NaC2H3O2(aq) Part A: Calculate the mass of acetic acid present in the vinegar sample? Part B: How many grams of acetic acid are in each mL of vinegar? Part C:How many grams of acetic acid would be in a 1.60 qt sample of this vinegar? Part D: How many...
Can you help me answer Question A? assuming 1.5M for NaOH Data Table 1. NaOH Titration...
Can you help me answer
Question A? assuming 1.5M for NaOH
Data Table 1. NaOH Titration Volume. Trial 1 Trial 2 Trial 3 Initial NaOH Final NaOH Total volume of Volume (mL) Volume (mL) NaOH used (mL) 9.1 0 9.1 9.8 .8 9.0 9.9 1.2 8.7 Average Volume of NaOH Used (ml): 8.93 Data Table 2. Concentration of CH3COOH in Vinegar. Average volume of Concentration CH3COOH NaOH used (mL) in vinegar (mol/L) 8.93 0.89 % CH3COOH in vinegar 5.34 X...
PART A. Titration of Vinegar Mass of empty flask Mass of flask and vinegar Mass of...
PART A. Titration of Vinegar Mass of empty flask Mass of flask and vinegar Mass of vinegar (9) Initial burette reading for NaOH (mL) Final burette reading for NaOH (mL) Volume of NaOH used (mL) Moles of NaOH used Trial 1 Trial 2 127.79 122.71 130.06 124.86 2.27 2.15 o 21.10 21.10 40.65 21.10 19.55 Moles of acetic acid that was titrated Mass of acetic acid that was titrated (9) Mass % of acetic acid in vinegar sample
I need it right now, please help me?? PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The...
I
need it right now, please help me??
PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...
1. A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known...
1. A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known mass of KHP was titrated with the NaOH solution until a light pink color appeared using phenolpthalein indicator. Using the volume of NaOH required to neutralize KHP and the number of moles of KHP titrated, the concentration of the NaOH solution was calculated. Molecular formula of Potassium hydrogen phthalate: HKC8H404 Mass of KHP used for standardization (g) 0.5100 Volume of NaOH required to neutralize...
A Weak Acid - Strong Base Titration Report Sheet Date: Name: Volume of CH3COOH (ml): Sample Code: { 10.00 mL Temperature: _22.0_ Initial Volume of NaOH (mL): 0.00 Molarity of NaOH (from label): _0.1013__ RUN 1 From LabQuest Titration Curve From 1st Derivative From Printed Titration Curve Instructor's Approval of LabQuest Data Volume of NaOH at Equivalence Pt (mL) 12.00mL 12.65mL Average Volume of NaOH at Equivalence Pt Include printed graphs of titration curve and 1st Derivation with Report Sheet...
I need help calculating the mass percent and with the post lab
question #2.
Part 1 Mass Initial | Final Vol Nall Moles concen. KPHCG (ML) I (m2) Used (m2) KHP (mol)/NaOH(M) 0.28470.00 13.60r 13.600 10.00- 0.1025 2 UZ + ZANT 13.600 24.45 1 10.85 0.001128 10.40 Aug NaOH Concentration (M):0.1032 Part2 Vinegar identification # 4 Vinegar sample date: (011/ Vol Vinegat Initial Final Yol NaOH Mol Acotic Mass Acctic Mass % Titr ULST I OML Used (ml) Acid (mol)...
A vinegar titration was completed using a pH meter as an indicator of the changing pH. A 25.00 mL sample of diluted vinegar (diluted by a factor of 5) was placed in a beaker and subsequently titrated with 0.1098 M NaOH. A derivative curve of the titration suggested that the equivalence point occurred at 40.90 mL. Calculate the mass percent of CH_3COOH. (The density of vinegar is 1.008 g/mL.) Moles of base at the equivalence point = Moles of acid...
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
i
need all answers
Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar (6) Volume of Vinegar (ml) Density - 1.005 g/ml Initial NaOH volume in syringe (ml) Final NaOH volume in syringe (ml) Volume of NaOH delivered (mL) Volume of NaOH delivered (L) Molarity of NaOH Moles of NaOH delivered Reaction of NaOH with Acetic Acid Moles of Acetic Acid in vinegar sample Molar mass of Acetic...
Can you help me answer
Question A? assuming 1.5M for NaOH
Data Table 1. NaOH Titration Volume. Trial 1 Trial 2 Trial 3 Initial NaOH Final NaOH Total volume of Volume (mL) Volume (mL) NaOH used (mL) 9.1 0 9.1 9.8 .8 9.0 9.9 1.2 8.7 Average Volume of NaOH Used (ml): 8.93 Data Table 2. Concentration of CH3COOH in Vinegar. Average volume of Concentration CH3COOH NaOH used (mL) in vinegar (mol/L) 8.93 0.89 % CH3COOH in vinegar 5.34 X...
PART A. Titration of Vinegar Mass of empty flask Mass of flask and vinegar Mass of vinegar (9) Initial burette reading for NaOH (mL) Final burette reading for NaOH (mL) Volume of NaOH used (mL) Moles of NaOH used Trial 1 Trial 2 127.79 122.71 130.06 124.86 2.27 2.15 o 21.10 21.10 40.65 21.10 19.55 Moles of acetic acid that was titrated Mass of acetic acid that was titrated (9) Mass % of acetic acid in vinegar sample
I
need it right now, please help me??
PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...
1. A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known mass of KHP was titrated with the NaOH solution until a light pink color appeared using phenolpthalein indicator. Using the volume of NaOH required to neutralize KHP and the number of moles of KHP titrated, the concentration of the NaOH solution was calculated. Molecular formula of Potassium hydrogen phthalate: HKC8H404 Mass of KHP used for standardization (g) 0.5100 Volume of NaOH required to neutralize...
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