Question

A Weak Acid - Strong Base Titration Report Sheet Date: Name: Volume of CH3COOH (ml): Sample Code: { 10.00 mL Temperature: _22.0_ Initial Volume of NaOH (mL): 0.00 Molarity of NaOH (from label): _0.1013__ RUN 1 From LabQuest Titration Curve From 1st Derivative From Printed Titration Curve Instructor's Approval of LabQuest Data Volume of NaOH at Equivalence Pt (mL) 12.00mL 12.65mL Average Volume of NaOH at Equivalence Pt Include printed graphs of titration curve and 1st Derivation with Report Sheet 12.33mL Moles of NaOH used at equivalence point: Moles of CH,COOH consumed at equivalence point: Molar Concentration of CH,COOH(aq): Show detailed calculations: Volume of NaOH at Half-Equivalence Point (ml): pH of CH3COOH(aq) at Half-Equivalence Point: K. of CH3COOH(aq): Show detailed calculation for Ke:

Answer 1

volume of CH₂ coolt = 10.00ml.avi Strength of CH3200H a SA average volume of Naoh at egivalene point = 12.33 ml, 2 V2 Strength of Nao H = 0.1013 (4) vis, 2 V2 S₂ - Siz V2 Sz. 12.33x 0.1013 Es 0.1249 (M) CH3200H & Noot = Che coona tiho. equalemole of acid consume egnalgomole of base. Mole of Naoh at esni valance point a 12.33m2 X 8.1013 mol = 12.33 mL x 0.1013 mai, = 1.249 X10-3 mol love Mole of Ct's cool conseme at egivakance point 21-2498103 mol 1 lit

Molar concentration of CH3 Cool) = 8.1249(0) derivative the volume of The staph and 254 Naot at half egnivalance points ata 12.33 1 2 3 6.165mL. In your graph, as you are not given here, you see the corresponding pH value at this volume. 6.188 for pH rs volume of Naolt graph. ts, pH = pleat doa [raff ] af half egnivelence - łacid ] point PP : pla o [salt} =[ acid] So that pH value will be = pka doz, to and praz-logka ika= 10 - Pka using kg = 10-PH this you can Calculate Kai