The following equation represents a saturated solution of lead chromate
PbCrO4(s) ⇌ Pb2+(aq) + CrO4 2– (aq) Ksp at 298 K was determined to be 1.8 x10^–14. What will happen if solid lead nitrate is added to the system?
(A) Have no effect.
(B) Reduce the value of the Ksp for lead chromate.
(C) Increase the value of Ksp for lead chromate.
(D) Shift the reaction to the right.
(E) Shift the reaction to the left.
Ksp of compound depends only on temperature.
So, Ksp will not change by changing concentration.
Pb(NO3)2 when added will give Pb2+ which is product in given equilibrium reaction of PbCrO4.
So, it is like adding more product and hence equilibrium will shift to left. This is called as common ion effect.
Answer: E
The following equation represents a saturated solution of lead chromate PbCrO4(s) ⇌ Pb2+(aq) + CrO4 2–...
Questions 1 & 2 refer to the solubility of lead chromate, PbCrO4: PbCrO4(s) = Pb2+ (aq) + CrO42-(aq) 1. The Ks for PbCrO4 is 2.0 x 10-16 at 25 °C. What is the solubility of PbCrO4 in mol L-?? a) 1.4 x 10-8 b) 2.8 x 10-8 c) 2.0 10-16 d) 7.1 x 10 e) 5.0 x 1015 2. If 5.0 mL of 1.0 x 10-'M Pb(NO3)2 is added to 5.0 mL of a solution of 1.0 x 10-0MK2Cr04, which...
Consider the dissolution equation of lead(II) chloride. PbCl2 (s) Pb2+ (aq) + 2 C1- (aq) Suppose you add 0.2331 g of PbCl2(s) to 50.0 mL of water. In the resulting saturated solution, you find that the concentration of Pb2+ (aq) is 0.0159 M and the concentration of Cl - (aq) is 0.0318 M. What is the value of the equilibrium constant, Ksp, for the dissolution of PbCl2? Answer:
Precipitation is the formation of an insoluble substance. For the equation AB(s)⇌A+(aq)+B−(aq), precipitation represents a shift to the left and the production of a solid. From Le Châtelier's principle, we know that when the product of the concentrations of A+ and B− gets above a certain level, the reaction will respond by shifting left to decrease the concentrations of A+ and B−. This critical level, Ksp, is a constant at a certain temperature. In this case, Q=[A+][B−], where Q is...
Pb2+(aq)+2CI1(aq), what is Q* when 9.0 mL of 0.055 M lead nitrate For the reaction: PbCl2(s) is added to 12 mL of 0.028 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3. Hint given in general feedback *Recall: Q is compared to Ksp to determine whether a precipitate forms. Answer 0.00577 X
For the reaction: PbCl2(s) ↔ Pb2+(aq)+2Cl1-(aq), what is Q* when 1.5 mL of 0.035 M lead nitrate is added to 13 mL of 0.010 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3. Hint given in general feedback *Recall: Q is compared to Ksp to determine whether a precipitate forms.
1) The molar solubility of PbI2 is 1.5X10-3 mol/L. PbI2(s) ? Pb2+(aq) + 2I-(aq) What is the molar concentration of iodide ion in a saturated PbI2 solution in mol/L? Hint: Consider mol ratios. Don't use scientific notation. Use 2 significant figures. ________ 2) The molar solubility of PbI2 is 1.5X10-3 mol/L. PbI2(s) ?Pb2+(aq) + 2I-(aq) Determine the solubility constant, ksp, for lead(II) iodide: ksp = [Pb2+][I-]2 Don't use scientific notation. Use 2 significant figures. ________ 3) How is the molar...
A solution contains 1.09x10-2 M calcium nitrate and 8.55x10-3 M lead acetate. Solid ammonium chromate is added slowly to this mixture. A. What is the formula of the substance that precipitates first? formula B. What is the concentration of chromate ion when this precipitation first begins? [Cro_2-1- M Solubility Product Constants (Ksp at 25 °C) Type Ksp Formula ZnCO3 1.5 x 10-11 Chlorides PbCl2 1.7 x 10-5 AgCi 1.8 10-10 Chromates BaCrO4 2.0 10-10 CaCrO4 7.1 x 10-4 PbCr04 1.8...
Equation: Pb(NO3)2(aq) + K2(CO3) --> PbCO3(s) + 2KNO3(aq) Net Ionic Equation: Pb2+ + CO32- --> PbCO3(s) lead (ii) nitrate concentration = 0.15 M, potassium carbonate concentration = 0.20 M Determine the percent yield if 0.1150 L of each reactant were allowed to react, and a mass of 5.0012 g of solid were obtained.
Lead ions can be precipitated from solution with KCl according to the following reaction: Pb2+(aq)+2KCl(aq) →PbCl2(s)+2K+(aq) When 28.5 g KCl is added to a solution containing 25.5 g Pb2+, a PbCl2 precipitate forms. The precipitate is filtered and dried and found to have a mass of 29.3 g. Determine the limiting reactant. Determine the theoretical yield of PbCl2. Determine the percent yield for the reaction.
MgF2(s) <--> Mg2+(aq) + 2 F–(aq) In a saturated solution of MgF2 at 18 0C, the concentration of Mg2+ is 1.21 x 10–3 molar. The equilibrium is represented by the equation above. (a) Write the expression for the solubility-product constant, Ksp, and calculate its value at 18 0C. (b) Calculate the equilibrium concentration of Mg2+ in 1.000 liter of saturated MgF2 solution at 18 0C to which 0.100 mole of solid KF has been added. The KF dissolves completely. Assume...