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Questions 1 & 2 refer to the solubility of lead chromate, PbCrO4: PbCrO4(s) = Pb2+ (aq) + CrO42-(aq) 1. The Ks for PbCrO4 is

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These questions are answered by using simple concept of solubility of the slats and their expression of the solubility product constant.

The answer is given in the image,

24 Ph Ci04 I 2.0 X10-16 Kip- Cрь]Гслод?-] 2. oxio-16 - S-S .4 xlo-8 Pb2t=.0ox10 CC093=.oxI0lo S.oXIo sp CPcr0 sp= (5.0XJ0S.ox

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