Question

Hi. can some one please explain me the solution for this question. the correct answer is D. thanks.

Questions 1& 2 refer to the solubility of lead chromate, PbCrO4 PbCrO4(s) Pb (aq) CrO4(aq) 2+ The Ksp for PbCrO4 is 2.0 x 101

Questions 1& 2 refer to the solubility of lead chromate, PbCrO4 PbCrO4(s) Pb (aq) CrO4(aq) 2+ The Ksp for PbCrO4 is 2.0 x 101

Questions 1& 2 refer to the solubility of lead chromate, PbCrO4 PbCrO4(s) Pb (aq) CrO4(aq) 2+ The Ksp for PbCrO4 is 2.0 x 101

i am asking for Q 2. sorry for many pictures.

Questions 1& 2 refer to the solubility of lead chromate, PbCrO4 PbCrO4(s) Pb (aq) CrO4(aq) 2+ The Ksp for PbCrO4 is 2.0 x 101

If 5.0 mL of 1.0 x 10 M Pb(No) is added to 5.0 mL of a solution of 1.0 x 1010 M KCrO 2. which statement is correct? a) The io

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Answer #1

Answer:-

This question is solved by firstly calculating the concentration of lead and chromate ions in the solution then Qsp is calculated and compared with Ksp.

The answer is given in the image,

2: [Pb2+] = 3.0x10*55.0 x10-6 M (68092] = 1.0x104°= 5.0X10-41 M Gsp=[Pb2+7 (68092-] Asp= (5.0x106) (5-0X1041) Qsp= 2.5x10-16

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