4. Calculate the pH of a 250.0 mL solution that has dissolved in it 0.000077 mol...

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Answer 1

Answer #1

moles of Ba(OH)2 = 0.000077 mol

moles of NaOH = 0.000030 mol

total moles of OH- = 0.000077 x 2 + 0.000030

= 0.000184 mol

concentration of OH- = 0.000184 / 0.250

= 7.36x10^-4 M

pOH = -log [OH-]

= -log (7.36 x 10^-4)

pOH = 3.133

pH = 10.87

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Answer 2

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