Question

An object is placed 48.0 cm from a concave spherical mirror with focal length of magnitude 18.5 cm. (a) Find the location of the image. cm in front of the mirror (b) What is the magnification of the image? (c) Is the image real or virtual? Oreal virtual (d) Is the image upright or inverted? upright O inverted

Answer 1

Hi,

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PART (a):

Given that,

Object distance,

u= 48 cm

Focal length of the mirror,

f = 18.5 cm

Therefore, location of image/image distance (V) is given by mirror equation:

$\frac{1}{f}=\frac{1}{u}+\frac{1}{V}$

T u 18.5 cm 48 cm

:: = 0.03322072 cm-1

V = 30.1 cm

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PART (b):

Magnification of the image is given by:

-V m = -30.1 cm 48 cm

:: m = -0.627

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PART (c):

Since the image can be formed on a screen, the image is REAL.

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PART (d):

We got a negative value for magnification.

Therefore, Image is INVERTED.

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