A 0.250 L buffer is made of 0.350 M [NaH2Po4] and 0.255M [Na2HPO4].
a. what is pH of this buffer?
b. What is pH of this buffer after 0.012 mols of HCl is added?
Please show work and all steps!!!!
A 0.250 L buffer is made of 0.350 M [NaH2Po4] and 0.255M [Na2HPO4]. a. what is...
A) A buffer solution contains 0.373 M NaH2PO4 and 0.348 M Na2HPO4. Determine the pH change when 0.083 mol HBr is added to 1.00 L of the buffer. pH change = ___ B) A buffer solution contains 0.330 M NH4Br and 0.379 M NH3 (ammonia). Determine the pH change when 0.086 mol HClO4is added to 1.00 L of the buffer. pH after addition − pH before addition = pH change = ___
a) What are the concentrations of Na2HPO4 and NaH2PO4 in a 0.30 M phosphate buffer solution pH 7.0? Use pKa 6.82 b) Describe how you would prepare 250 mL of the buffer in part (a) given that you have available to you a 1.0 M stock solution of NaH2PO4 and solid Na2HPO4(FW 141.96 g/mol). Provide your answer in milliliters of NaH2PO4 and grams of Na2HPO4. c) Suppose you use 100 ml of this buffer in an experiment and 0.003 mol...
A buffer solution contains 0.235 M NaH2PO4 and 0.371 M Na2HPO4 If 0.0297 moles of nitric acid are added to 225 mL of this buffer, what is the pH of the resulting solution ? (Assume that the volume change does not change upon adding nitric acid pH =
What is the pH of a 1.0 L buffer that is 0.10 M in Na2HPO4 and 0.15 M in NaH2PO4? Write the equilibrium reaction equation and corresponding Ka expression for the buffer. Ka for H2PO4- is 6.2 x 10^-8
Calculate the pH of a buffer solution that contains 0.56 M NaH2PO4 and 0.21M Na2HPO4 Calculate the change in pH if 0.050 g of solid NaOH is added to 200 mL of the solution in the problem above.
A buffer consists of 0.24 M NaH2PO4 and 0.47 M Na2HPO4. Given that the K values for H3PO4 are, Ka1 = 7.2 x 10-3, Ka2 = 6.3 x 10-8, and Ka3 = 4.2 x 10-13, calculate the pH for this buffer.
A buffer consists of 0.34 M NaH2PO4 and 0.28 M Na2HPO4. Given that the values for H3PO4 are, Ka1 -7.2 x 10-3 Ka2 = 6.3 x 10-8 and Ka3 = 4.2x 10-13, calculate the pH for this buffer. Selected Answer: Correct Answer: [None Given] 7.12 10.02
A buffer consists of 0.24 M NaH2PO4 and 0.47 M Na2HPO4. Given that the K values for H3PO4 are, Ka1 = 7.2 x 10-3, Ka2 = 6.3 x 10-8, and Ka3 = 4.2 x 10-13, calculate the pH for this buffer. I know that the answer is 7.49 because pH = -log(6.3 x 10-8) + log(0.47/0.24). What I want to know is WHY 6.3 x 10-8 was used instead of Ka1 or Ka3. Thanks.
consider 100.0 ml of a buffer solution that contains [NaCH3COO]=[CH3COOH]=0.250 M a) what is the pH of this buffer? b) what should the ph of the buffer be after 50.0ml of water is added? explain c) wtite balanced net ionic for the reaction that occurs whrn 1.0 M HCl ir added to this buffer. d) after adding 10.0 ml of 1.0 M HCl what will the ph of the solution be? e) as more 1.0 M HCl is slowly added...
A student was told to make a pH = 7.5 buffer from sodium dihydrogen phosphate and sodium hydrogen phosphate with an ionic strength of 0.10 a) What concentration of Na2HPO4 and NaH2PO4 need to be used? b) If 10.0 mL of 1.00 M Hbr is added to 1.00 L of this buffer, what is the pH? Please show work.