Work-done to stretch a spring is given by:
W = (1/2)k*x^2
given that
W = 4 J and x stretch = 10 cm = 0.1 m
So,
k = 2W/x^2
k = 2*4/0.1^2 = 800 N/m
Now to stretch it additionally 5 cm,
total stretch = 10 cm + 5 cm = 15 cm = 0.15 m
W = (1/2)k*x^2 = 800*0.15^2/2
W = 9 J
Extra work required = 9 J - 4 J = 5 J
Correct option is E.
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