Solution :
Given that,
Point estimate = sample mean = = 21
Population standard deviation = = 2
Sample size = n = 100
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * ( 2 / 100)
= 0.39
At 95% confidence interval estimate of the population mean is,
- E < < + E
21 - 0.39 < < 21 + 0.39
20.61 < < 21.39
The 95% confidence interval is from (20.61 to 21.39)
Score: 0 of 1 pt For the provided sample mean, sample size, and population standard deviation,...
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