Question

is treated with the following reagents. Predict the products formed when, 7. a. LIAIH4 in THF, then HCI in water b.EtMgBrin THF, then NH4CI in H2O NaOH in H2O. b.

Answer 1

willin centre of (1) LiAlHu in THE (i) Watch Hal in Ho :. An imine is reduced by hydride ion to form an amine. The mechanism is quite similar. to reduction of carbonyl group ie. aldehydes or Ketones with hydride in The 40 from kel .. . at amine

Therefore I The first step is hydride ion reacting at electrophillic carbon atom of imine .. The anion that is formed is then protonated in second step (via hell in H2O) → Note that the acid workep is done in reperate step due to incompatibility of liAltly with brotic solvents. of imine → This type of Reduction of an to give amine REDUCTIVE AMINATION ed (1) Et Mg Br in The (1) NHU in Ho. This reaction is similar to above reaction (). In (a) the nucleophile was He but here the пшоор hiu u , ще

→: CH Mo attacks at the electrophillic centre of imine then then a small workup with NHU THE - Agains the workup is done in diff step due to incompatibility of Grignard Reagent with protic solvent with tho. CH CH Mg Br . NHull 1H₂O (Workup) © or 5

. acid-base Ran " ": This is the basic hydrolysis - at the electrophillic centre ... amine departs as leaving of imines, the On attack and then the group. .