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An aqueous solution contains 0.380 M methylamine (CH3NH2).   How many mL of 0.211 M hydrochloric acid...

An aqueous solution contains 0.380 M methylamine (CH3NH2).  

How many mL of 0.211 M hydrochloric acid would have to be added to 250 mL of this solution in order to prepare a buffer with a pH of 10.800.

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Answer #1

Mole CHe2 0.250 L X 6380 mele L 0.095 0le -7 mole Rep mole tep added PH 10.8oo poH 14-10.800 3.200 Pro Of CHy NH 3.38 (Lit va

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