An aqueous solution contains 0.489 M acetic acid. How many mL of 0.257 M potassium hydroxide...

Question

Question

An aqueous solution contains 0.489 M acetic acid. How many mL of 0.257 M potassium hydroxide would have to be added to 150 mL

Answer 1

Answer #1

number of moles = Molarity Volume volume of CH3COOH = 150 mL = 0.150 L initial no. of moles of CH3COOH = 0.489 x 0.150 = 0.07

Answer 2

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