The molecules A and B are made of C, H and O. The molecules were combusted and the combustion product was analyzed. Use the information below to determine the empirical formula for each molecule.
Acid |
Mass Combusted (g) |
Mass C (g) |
Mass H (g) |
Mass of O (g) |
A |
2.233 |
0.914 |
0.1015 |
1.218 |
B |
1.564 |
0.9878 |
0.0822 |
0.4944 |
A)
we have mass of each elements as:
C: 0.914 g
H: 0.1015 g
O: 1.218 g
Divide by molar mass to get number of moles of each:
C: 0.914/12.01 = 0.0761
H: 0.1015/1.008 = 0.1007
O: 1.218/16.0 = 0.0761
Divide by smallest
C: 0.0761/0.0761 = 1
H: 0.1007/0.0761 = 4/3
O: 0.0761/0.0761 = 1
Multiply by 3 to get simplest whole number ratio:
C: 1*3 = 3
H: 4/3*3 = 4
O: 1*3 = 3
So empirical formula is:C3H4O3
Answer: C3H4O3
B)
we have mass of each elements as:
C: 0.9878 g
H: 0.0822 g
O: 0.4944 g
Divide by molar mass to get number of moles of each:
C: 0.9878/12.01 = 0.0822
H: 0.0822/1.008 = 0.0815
O: 0.4944/16.0 = 0.0309
Divide by smallest:
C: 0.0822/0.0309 = 8/3
H: 0.0815/0.0309 = 8/3
O: 0.0309/0.0309 = 1
Multiply by 3 to get simplest whole number ratio:
C: 8/3*3 = 8
H: 8/3*3 = 8
O: 1*3 = 3
So empirical formula is:C8H8O3
Answer: C8H8O3
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