How many grams of Na2CO3 are needed to prepare 25.0 mL of a 2.00%(m/v) Na2 CO3...

Question

Question

Answer 1

Answer #1

49)
Given:
(m/v)% = 2.00 %
Volume of solution = 25.0 mL

Use:
(m/v)% = mass of Na2CO3 * 100 / Volume of solution
2.00 = mass of Na2CO3 * 100 / 25.0
mass of Na2CO3 = 0.500 g

Answer: 0.500 g

Only 1 question at a time please

Answer 2

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