2. A 2.0-L reaction flask initially contains 0.010 mol CO, 0.80 mol H2, and 0.50 mol...

Question

Question

Answer 1

Answer #1

Initial [CO] = mol of CO / volume in L

= 0.010 mol / 2.0 L

= 0.0050 M

Initial [H2] = mol of H2 / volume in L

= 0.80 mol / 2.0 L

= 0.40 M

Initial [CH3OH] = mol of CH3OH / volume in L

= 0.50 mol / 2.0 L

= 0.25 M

Use:

Qc = [CH3OH] / [CO][H2]^2

= 0.25 / (0.0050 * 0.40^2)

= 3.1*10^2

Since Qc is greater than Kc, reverse reaction will be favoured

Answer: reverse

Answer 2

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