Place the following salts in order of increasing lattice energy. NaCl, KBr, BeO
I really need help with this. I know that ionic charge and size matters with lattice energy, but I am confused with comparing size. There are two ion in one molecule! which one should I compare?
Lattice energy depends on:
Higher charge means higher lattice energy
Smaller size of ions means more lattice energy
In the same order of priority i.e charge over size
From this BeO has the highest lattice energy.
Now between NaCl and KBr, Na and Cl are smaller than K and Br meaning NaCl has more lattice energy
The order is : KBr < NaCl < BeO
Place the following salts in order of increasing lattice energy. NaCl, KBr, BeO I really need...
Arrange NaCl, KBr and BeO in increasing lattice energy. Then do the same for BaO,CaO and KI separately.
Place the following in order of increasing magnitude of lattice energy. CaS MgS BeO
Place the following salts in order of increasing lattice energy. Bao, CaO, KI (33% penalty for each incorrect response) KĨ < Cao < Bao KI < BaO < CaO Ba0 < KI < CaO BaO < CaO Ý KI Cao < BaO KI Jump to... CaO Ý KI < BaO 3, 11:59
Arrange the following ionic compounds in order of increasing (ie. more negative) lattice energy LiF SrO NaCl Li2O Al2O3 KBr MgO
1. Arrange the following in order of INCREASING lattice energy: NaF, MgS, K2S, and KBr.
Rank the following ionic compounds in order of increasing magnitude of lattice energy (i.e., the absolute value of the lattice energy with the largest magnitude listed last): MgO, RbI, MgCl2, NaCl
Place the following in order of increasing magnitude of lattice energy. MgO Nal Ba O
Place the following in order of increasing magnitude of lattice energy. MgO LiI Ba S
Place the following salts in order of increasing water solubility: i. Fe(OH)2 Ksp = 7.9 × 10−16 ii. CoCO3 Ksp = 1.0 × 10−10 iii. Ag2CrO4 Ksp = 1.2 × 10−12
Consider the following set of quantum numbers and place them in order of increasing energy I. n = 4, l = 0, ml = 0, ms = -1/2 II. n = 4, l = 2, ml = -1, ms = -1/2 III. n = 5, l = 0, ml = 0, ms = +1/2 I < II < III III < II < I I < III < II II < III < I III < I < II