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The electric potential due to a charge q at a distance l = Kq/l
A)For part A, take a small charge dQ of length dx. Therefore small potential dv due to dq = kdq/√z 2 + x 2
We integrate this potential for dx varying from - L/2 to + L/2
( Also we have written x and z in the form of tan theta and sec theta for easier integration)
B) Take a charge dQ of length Dy at a distance y from point B.
Therefore, dv= kdq/y
Integrate dv from length y varying from (- L/2 + x) to (+L/2 + x)
The correct answers are already given. What you have to do is how to get those...
The correct answer is already given. What you have to do is how to get this answer. 60 points (10 points per problem)- Problem 1: The figure on the right shows a thin rod of length L. A total charge of Q is distributed uniformly along its length. Find an expression for the vector electric field at point P. Give your answer in component form. Answer:
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