Question

***Please solve the problem below using R, and provide the R code you used in order...

***Please solve the problem below using R, and provide the R code you used in order to do so***

The mean undergraduate cost for tuition, fees, room, and board for four-year institutions was $26,489 for the 2004-2005 academic year. Suppose that the standard deviation of the distribution was $3204 and that 36 four-year institutions are randomly selected. Find the probability that the sample mean cost for these 36 schools is

a. Less than $25,000

b. Greater than $26,000

c. Between $24,000 and $26,000

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Answer #1

Solution:

Given:  The mean undergraduate cost for tuition, fees, room, and board for four-year institutions was $26,489 for the 2004-2005 academic year.

thus Mean = u=26489

the standard deviation of the distribution was $3204

thus standard deviation = 0 = 3204

Sample size = n = 36

We have to find:

Part a) P(  the sample mean cost for these 36 schools is less than $25,000) =..............?

Pla <25000) = ........

We use following R code to find this probability:

pnorm( x , mean=_____, sd=_____/sqrt(n))

pnorm(25000, mean=26489, sd=3204/sqrt(36))

0.002648541

that is:

P T < 25000) = 0.0026

Part b)

P(  the sample mean cost for these 36 schools is  Greater than $26,000) =............?

PT> 26000) = ........

pnorm(26000, mean=26489, sd=3204/sqrt(36),lower.tail=FALSE)

0.8200958

thus

PT> 26000) = 0.8200958

PI > 26000) = 0.8201

Part c)

P(  the sample mean cost for these 36 schools is Between $24,000 and $26,000) =...........?

P(24000 < i < 26000) = .........

We use R code:

pnorm(26000, mean=26489, sd=3204/sqrt(36))-pnorm(24000, mean=26489, sd=3204/sqrt(36))

0.1799026

thus

P(24000 < i < 26000) = 0.1799026

P(24000 < i < 26000) = 0.1799

R RGui (32-bit) - [R Console] R File Edit View Misc Packages Windows Help Platform: i386-w64-mingw32/i386 (32-bit) R is free

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