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6- Use Table 11.2 Solubilities of Some lonic Compounds to decide if a solution containing 0.000092 g of AgCl per 100 g of H
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12) NaOH is more soluble in CH3OH

4) Moles of C6H12O6 = mass/molar mass = 332/180 = 1.84 moles

Molarity of solution = moles/volume in liters = 1.84/4.66 = 0.395 mol/liter ....Answer

6) Moles of NH4Br = molarity * volume in liters = 0.228 * (88.9/1000) = 0.0203 ....Answer

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6- Use Table 11.2 "Solubilities of Some lonic Compounds" to decide if a solution containing 0.000092...
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