What is the pH of a 2.9 x 10-5 M solution of HBr?
Given:
[HBr] = 2.9*10^-5 M
So,
[H+] = 2.9*10^-5 M
use:
pH = -log [H+]
= -log (2.9*10^-5)
= 4.54
Answer: 4.54
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