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Problem 2 (3 pts.) Water is emerging from a circular faucet with a diameter 2.6 cm, as shown in Fig. 2. (a) In order to solve this problem, you may assume that the water is flowing down with the free-fall acceleration g = 9.8 m/s. Please prove this assumption using Bernoulli equation. (6) If the flow rate (volume of the water which exits the faucet per unit time) is R= 127 cm3/s, at what distance H below the tap its speed will be v2 = 1.2 m/s? (c) For which flow rate Rnew the speed of the water at distance H below the tap would be exactly twice compared to its initial speed right next to the tap? Id=2.6 cm H-? to2 U2 = 0.42" Figure 2: Schematic graph for Problem 2.

Answer 1

Re AU ant faueet सि (एँ' ) (मेड) 121x l0 F1Sxl52)-m ০-২3৭2 w | s. 2-- Re uratu came -Patrisure fiaalbaeiplat र 2 2 >ebove is Epesizieltzet Equisaleut +O

عانعلا 20 29-8) (H Layu-04or1216=2(9-8) HEO0705M H=7.0SCn 2 2- 9-8)(0.070) 3५ V,- 0.6136 m 4A 2 Rnu= 3.603X10 यमी K360-Cu see

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