A thin stream of water flows smoothly from a faucet and falls straight down. At one...

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A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of

Answer 1

Answer #1

Solution -

Applying the continuity equations -

A₁V₁= A₂V₂ ( A = Area , V = Velocity )

π x D₁² x V₁ = π x D₂² x V₂

V_{2 =} V₁( D₁² / D₂² )

= 1.47 x [1 / ( 0.859)² ] ( Note - D₂ / D₁ = 0.859)

= 1.992 m/s

Apply the energy conservation

(1/2) x m x V₂² - (1/2) x m x V₁² = mgh

h = ( V₂² - V₁² ) / 2g

= (1.992² - 1.47² ) / (2 x 9.81 )

= 0.0921 m = 9.21 cms

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Answer 2

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