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Using the electrochemical series and the standard reduction potential tables in your text, would you be able to form a galvan
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Answer #1

EAg+/Ag = +0.222 V

ECr3+/Cr = -0.41 V

We see that it is possible to obtain an electrochemical cell using Cr anode and Ag cathopde because the net E of cell is positive as given by:

Ecell = EAg+/Ag - ECr3+/Cr = +0.222 - (-0.41) = +0.632 V

Overall balanced equation:

3 Ag+(aq) + Cr(s)\rightarrow 3 Ag(s) + Cr3+(aq)

Electrolytes : Cathode half cell : AgNO3

Anode Half cell : Cr(NO3)3

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