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A spring has a force constant of 2.000 N/m. The work done in stretching the spring from a length of 30.0 cm to a length of 36

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Answer #1

a) 3.6 J is correct answer

Solution :-

Spring constant k = 2000 N/m

Stretch in the spring ∆x = ( 36 - 30 ) cm = 6cm = .06 m

Work done in stretching a spiring is given by = 1/2 ( k . ∆x²)

= 1/2 ( 2000 X 0.06²)

= 1/2 X 2000 X .0036

= 3.6 J

So, the work done in stretching a string from 30 cm to 36 cm is 3.60 J

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