A) physical memory size =2^32 bytes
page size = 2^10 bytes
logical address space : 2^16 bytes
A)
Entries in page table = no of pages in virtual memory
= 2^16
==========================================
B)frames in physical memory = size of physical memory/size of the page frame
=2^32/2^10
=2^22
no of bits in physical memory=22
bits in each page table entry when each page table entry contains a valid/invalid bit. =22+1
=23
Consider a simple paging system with the following parameters: 232 bytes of physical memory; page size...
1. Consider a simple paging system with the following parameters: 232 bytes of physical memory; page size of 210 bytes; 216 pages of logical address space. How many bits are in a logical address? How many bytes are in a frame! How many bits in the physical address specify the frame? How many entries are in the page table? How many bits are in each page table entry? Assume each page table entry contains a valid/invalid bit. 2. Consider a...
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A simple paging system has a memory size of 256 bytes and a page size of 16 bytes. i. What is the size of the page table? ii. How many bits exist for an address, assuming 1-byte incremental addressing? iii. State p and d values (i.e. the page number and the offset). iv. Perform address translation of 64 bytes to physical address space using the page table below. 0 8 1 6 2 3 3 11 4 7
6) Paging [26 pts] Suppose you have a computer system with a 38-bit logical address, page size of 16K, and 4 bytes per page table entry a) How many pages are there in the logical address space? Suppose we use two level paging and each page table can fit completely in a frame. [4 pts] How many pages? [2 pts] Show your calculations here: b) For the above-mentioned system, give the breakup of logical address bits clearly indicating number of...
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Consider a logical address space of 8 pages; each page is 2048 byte long, mapped onto a physical memory of 64 frames.(i) How many bits are there in the logical address and how many bits are there in the physical address?(ii) A 6284 bytes program is to be loaded in some of the available frames ={10,8,40,25,3, 15,56,18,12,35} . Show the contents of the program's page table.(iii) What is the size of the internal fragmentation?(iv) Convert the following logical addresses 2249...
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