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How many mL of 1.2M HCl are needed to titrate 5.00mL of 1.75mL of Ba(OH)2 ?

How many mL of 1.2M HCI are need to titrate 5.00mL of 1.75mL of Ba(OH)2?
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Answer #1

Equation: Ba(OH), (aq) + 2HCl(aq) →→ BaCl, (aq) + 2H,0(1) 1L 1.75 mol Ba(OH), No of moles of Ba(OH), = 5.00 mLx 3.0 ML 1000 m

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