How many millilters of 0.0710 M Ba(OH)2 are required to titrate 200.7 mL of 0.0150 M...

Question

Question

How many millilters of 0.0710 M Ba(OH)2 are required to titrate 200.7 mL of 0.0150 M HNO3

Answer 1

Answer #1

ans) milli moles of Ba( OH) 2 = milli moles of HNO3

balanced eq Ba( OH) 2 + 2 HNO3 $\rightarrow$ Ba( NO3) ₂ + 2H2O

1* 0.0710 * X = 0.0150 *200.7 * 2

X = 84.80 ml

thank u

Answer 2

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