Calculate the volume of 0.376 M Ba(OH)2 required to titrate a 15.00 mL sample of 0.281 M HBr. The answer should be in mL and in to 2 decimal places
Gram equivalent of Ba(OH)2 = Gram equivalent of HBr
M1 V1 X1. =. M2V2X2
Where, M = molarity, V = volume and X = n-factor
0.376 × V1 × 2. =. 0.281 × 15 × 1
V1 = (0.281 × 15)/(0.376 × 2)
V1 = 5.61 mL
Calculate the volume of 0.376 M Ba(OH)2 required to titrate a 15.00 mL sample of 0.281...
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