Question

Assignment - Next week • What is the molar concentration (molarity) of KOH in 350 ml solution that contains 34 g of KOH? - 607 ) . 60°7. MOL 3910 +16 + 1.008 735L You have 1250 mL of a 0.4 M solution of KMnO4. How many grams of KMnO, are dissolved in the solution? 350 MY ME 1734.28 • You have a 0.8 M solution of AgNO3. There are 12 g of AgNO3 dissolved in the solution. What is the volume of the solution?

Answer 1

Molarity of a solution is given as ,

Molarity = moles/volume in liters

Number of moles = mass/molar mass

1. Molar mass of KOH = 56.11 g/mol

Moles of KOH = 34/56.11

= 0.61 moles

Volume = 350 ml

1 L = 1000 ml

Volume = 0.350 L

Molarity = 0.61/0.350

= 1.7 M

2. Molar mass of KMnO4 = 158.03 g/mol

Volume = 1.25 L

Moles = 1.25 × 0.4

= 0.5 moles

Mass of KMnO4 = 0.5 mol × 158.03 g/mol

= 79.02 grams

3. Molar mass of AgNO3 = 169.87 g/mol

Moles of AgNO3 = 12/169.87

= 0.071 moles

Volume = 0.071/0.8

= 0.0888 L

Volume = 88.8 ml