useful formula is
heat q= mcdT
q= 1940 j
dT = change in temperature dT = 44.2 -23 C =21.2
liquid ethanol, specific heat c=112.4 J/(mol K)
mass m = q/cdT = 1940 j/112.4 J/(mol K)* 21.2 K = 0. 81414 kg =
814.1 g
round to 2 significant figures
m = 810 g
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You may want to reference (Pages 373 - 379) Section 0.4 while completing this problem. An...
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