A spherically symmetric charge distribution produces the electric field E⃗ =( 4600 r2)r^N/C, where r is in...
A spherically symmetric charge distribution produces the electric field E⃗ =( 4600 r2)r^N/C, where r is in m.
What is the electric field strength at r = 15.0 cm ?
What is the electric flux through a 30.0-cm-diameter spherical surface that is concentric with the charge distribution?
How much charge is inside this 30.0-cm-diameter spherical surface?
Homework Answers
Ans:
- E = 4600r2 N/C
E = 4600(0.15)2 = 103.5 N/C
- 30 cm = Diameter
15 cm = Radius
φ = EAsphere
= (103.5)(4 * Pi * (0.15)2) = 29.249 Nm2/C
- For charge
φ = q/ϵ0
q = φ * ϵ0 = (29.249)(8.85 * 10-12) = 2.58 * 10-10 C
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