Answer to question#5:
The
is the standard enthalpy of formation. All elements which are in
standard states have the standard enthalpy of formation value zero.
Among the options I2(l), the molecular iodine
is in dissolved state. the standard state of molecular iodine is
solid. Thus the deltaHof is not zero.
H2O(l) is formed from the reaction of
H2 (g) and O2 (g). Here, in the reaction the
reactants and product are not in same state. Therefore,
deltaHof is not zero. For H+(aq);
the H+ is considered gas. In H+(aq), the H+ ion is surrounded by
water molecules and is in dissolved state. Therefore,
deltaHof is not zero. Only for Hg(l)
is in standard state because elemental mercury is liquid.
Answer to question#8:
need a clear explanation on number 5 and 8 pretty please dont really understand what deltaH=0...
need help with 6, 7, and 8 can seem to understand why these
are the answer
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5 questions please show work
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