Question

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6. The following data refer to the hydrolysis of 2-bromo-2-methylpropane, by aqueous sodium hydroxide at 25 °C. (CH3)3CBr+ OH -(CHa) COH + Br Experiment # Concentration of Concentration of Initial rate of 2-bromo-2- hydroxide ions (M) hydrolysis (M/'s) methylpropane (M) 1 0.100 0.500 0.0020 2 0.100 0.250 0.0020 3 0.075 0.250 0.0015 4 0.050 0.250 0.0010 5 0.025 0.250 0.0005 What is the order of reaction with respect to a. i. 2-bromo-2-methylpropane i. Hydroxide ion? What is the overall order of the reaction? b. c. Write the simplified rate expression for the reaction d. Calculate the rate constant e. Give the units of the rate constant Calculate the rate when the concentration of the alkane and the hydroxide ion are 0.435 M and 0.0684 M respectively. f.

Answer 1

The answer is

17 i) when the concentration of of ion is constant ie 0.25om, and the conc. of (CH₂)2 CB8 is doubled from 0.025 M to 0.050 m the rate oy reaction is also doubled refrom 0.0005 N/S to 0.0010 M/S - we know that on doubleng the conc. of reactant 14 the t rate oy reaction chets doubled .. Then the order with respect to the reactant is 1. . The order to not (CH₃) SB8 is to

11 OH is coobled when the conc. of OH- is cloon 980m 0.250 M to 0.5oom at com conco4 ICHolac B8 ie 0.10OM The rate oy reaction do not change i. The order witot OH-ion - 2080- bli. The overall order of 2xD = order wirot (CH₂)₂(B8 + order collit ОН- - 1 to - C) - The overall order is 1. rate = K [CH₃) 2C 1387 [OH-] . rate = k [ (CH 3 ) ₂ CB 87 x 7 Ci. [OH] = 1) Date = K [(CH3), CBOT 14 rate=0.0020 M/S [(CH₂)2 CB2] = 0.im . . rate=k [ (CH3) CB87 KI rate 0.002 M/S T(CH),C BOJ OTMI e ) - 0. 02 i date constant = K = 0.02 ser el.: Unit of K = sech AL [(CH3C B8] = 0.4541 K = 0.02seit Prate: 0.0087 date= K[CH₂ ) f Br] = 0+02X0.4352 MIS 0.0087141k Ni unit on constanter