Question 17 (3 points) The following set of data was obtained by the method of initial...
2. The following set of data was obtained by the method of initial rates for the reaction: BrO3- + 6H* + 5B Experiment [Br03 M 0.10 2 0.20 3 0.20 4 0.10 3Br2 + 3H2O [H]M [Br] M 0.10 0.10 0.10 0.10 0.10 0.15 0.25 0.10 Rate [mol/(L )] 8.0 x 10+ 1.6 x 10-3 2.4 x 10- 5.0 x 10-2 What is the rate law for the reaction? Show all work to receive credit. (5 points)
(CH3)3CBr + H2O → (CH3)3COH + HBT Initial (CH3),CBr] Initial [H0] Experiment1 Experiment 2 Experiment 3 mol L 5.0 x 10 5.0 x 104 1.0 x 10" mol L 2.0 x 10 4.0 x 10 4.0 x 10 Initial rate mol L 'min 2.0 x 10 2.0 x 10 4.0 x 10 a. ratek [(CH3)3CBr] O b. ratek [H2O] cratek [(CH3)3CBr)[H20] d. rate=k[(CH3),CBr] [H2012 L Moving to another question will save this response.
I need the answers in details with explanation thanks in advance! first question: second question: 7) The reaction (CH3)3CBr + OH → (CH3)3COH + Br in a certain solvent is first order with respect to (CH3)3CBr and zero order with respect to OH-. In several experiments, the rate constant k was determined at different temperatures. A plot of In(k) versus 1/T was constructed resulting in a straight line with a slope of -1.10 X 104 K and y-intercept of 33.5....
41 The following data was experimentally obtained for the reaction: 2 of 2 (CH3)3CBr + H2O → (CH3)3COH + HBr t(h) (CH3)2CBr (mol/L) 0 10.39 x 102 3.15 8.96 x 102 6.20 7.76 x 102 10 6.39 x 102 18.30 3.53 x 102 30.80 2.07 x 102 a) Make the appropriate graphs and from them determine the order of reaction in relation to (CH3),CBr. In other words, the rate law expression will be like: Rate = k [(CH3)3CBr]" By concluding...
The following initial rate data are for the reaction of UO2 with hydrogen ion in aqueous solution xperiment nitial Rate, Ms1 95x10-3 1.18x102 90x10-3 36x10-2 85x10-3 70x10 85x10-3 70x10-3 826 826 1.65 1.65 Complete the rate law for this reaction in the box below. Use the form kļAlm [Bln , where '1' is understood for m or n and concentrations taken to the zero power do not appear. Don't enter 1 for m or n Rate- From these data, the...
7. Consider the following second-order reaction: 2X ? Y. The initial concentration of X is 0.50 M. It takes 30 minutes for the concentration of X to decrease to 35% of its initial value. Calculate the rate constant for this second-order reaction. A. 0.0330 Mmin B. 0.124 M-min-1 C. 0.185 M-'min-1 D.0.367 Mmin-1 E. 2.48 M-min-1
QUESTION 6 For the second order reaction A products, the following data are obtained: [A] - 3.024 M, t = 0 min [A] = 2.935 M. t = 1.0 min [A] = 2.852 M. t = 2.0 min What is the rate constant, k? A. 3.6% 10-3 M-1 min-1 B. 1.4 * 10-2 M-1 min-1 C.2.2 x 10-2 M-1 min-1 0.9.7 * 10-3 M-1 min-1 E. 1.0 10-2 M-1 min-1
March 4, 2020 5. The reaction of 'butyl-bromide (CH3)3CBr with water is represented by the equation: (CH3),CBr + H2O → (CH3)3COH + HBr The following data were obtained from three experiments: Experiment 1 Experiment 2 Experiment 3 Initial [(CH3)3CBr mol L-1 5.0 x 10-2 5.0 x 10-2 1.0 x 10-1 Initial [H0] mol L 2.0 x 10-2 4.0 x 102 | 4.0 x 10-2 Initial rate mol L-'min 2.0 x 10-6 2.0 x 10-6 4.0 x 10-6 a) What is...
Question 3 (Mandatory) (5 points) The rate constant of a first-order decomposition reaction is 0.0147 s. If the initial concentration of reactant is 0.178 M, what is the concentration of reactant after 30.0 seconds? a) 8.72 x 10 M Ob) 0.0785 M Oc) 0,115 M O d) 0.643 M e) 0.0645 M Question 4 (Mandatory) (5 points) The reaction quotient, . for a system is 1.6 x 104. If the equilibrium constant for the system at some temperature 8.5 x...
each reactant from the following data. Show work, of co inspection) method (method of initial rates), calculate the order in course! Consult your text book if needed. wherex isonder(Rotel)=(C Ratel Rate2 log a og Con) Concentrato! ) ' 12/ = log( Order = use this: A Run Initial [A] Initial IB] 2 C of E 0.20M 0.20M 0.40M 0.20M 0.20M 0.20M 0.20M 0.60M Initial IC 0.20M 0.30M 0.30M 0.30M 2.42x106 M/min 2.44x106 M/min 9.67x106 M/min 7.23x10 M/min Remember, the idea...