Question 1.
According to Gay-Lussac's law:
The pressure of the gas is directly related to its absolute temperature.
i.e. P1/T1 = P2/T2
Where P1 is the pressure of the gas at an absolute temperature T1.
P2 is the pressure of the gas at an absolute temperature T2.
760 torr/(300+273.15) K = 10 torr/T2
i.e. T2 = 7.54 K
i.e. T2 = (7.54 - 273.15) oC = -265.61 oC
What would you expect the observed boiling point to be at 10 torrs of a liquid...
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