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A student determines that 13.67 mL of NaOH delivering 0.00336 moles of NaOH were required to...
A 21.70 mL volume of 0.0940 M NaOH is required to reach the phenolphthalein endpoint in...
A 21.70 mL volume of 0.0940 M NaOH is required to reach the phenolphthalein endpoint in the titration of a 3.06 g sample of vinegar. a. Calculate the number of moles of acetic acid in the vinegar sample. Calculate the mass of acetic acid in the vinegar sample. The molar mass of acetic acid is 60.05 g/mol. b. Calculate the percent by mass of acetic acid in the vinegar sample. Assume the density of the vinegar is 1.00 g/mL. Express...
Uz moi or acetic acid reacts Question 10 (1 point) A student finds that 12.43 milliliters...
Uz moi or acetic acid reacts Question 10 (1 point) A student finds that 12.43 milliliters of NaOH solution with a concentration of 0.155 M are needed to neutralize a vinegar sample. How many moles of NaOH were added to the sample? Your Answer: Answer units Question 11 (1 point) A student determines that 0.00170 moles of NaOH were required to neutralize the acetic acid in a sample of vinegar. How many moles of acetic acid must have been present...
9. A 4-gram sample of vinegar containing acetic acid CH3C 0.2 M NaOH. After 15 mL...
9. A 4-gram sample of vinegar containing acetic acid CH3C 0.2 M NaOH. After 15 mL of NaOH was added, the stoichiometric p reached as evidenced by the change in color of the indicator. Calculate percent of acetic acid in the vinegar. Molar mass of acetic acid=60.05 ining acetic acid CH3COOH was titrated with s added, the stoichiometric point was or of the indicator. Calculate the mass
A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar...
A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar needs 45.0 mL of 0.135 M NaOH to reach the equivalence point in a titration CH3COOH(aq)+NaOH(aq)→H2O(l)+NaC2H3O2(aq) Part A: Calculate the mass of acetic acid present in the vinegar sample? Part B: How many grams of acetic acid are in each mL of vinegar? Part C:How many grams of acetic acid would be in a 1.60 qt sample of this vinegar? Part D: How many...
1. A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known...
1. A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known mass of KHP was titrated with the NaOH solution until a light pink color appeared using phenolpthalein indicator. Using the volume of NaOH required to neutralize KHP and the number of moles of KHP titrated, the concentration of the NaOH solution was calculated. Molecular formula of Potassium hydrogen phthalate: HKC8H404 Mass of KHP used for standardization (g) 0.5100 Volume of NaOH required to neutralize...
Exercise 1 - Questions 1. The manufacturer of the vinegar used in the experiment stated that...
Exercise 1 - Questions 1. The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percent error between your result and the manufacturer statement? Show your work 30 Using the following equation, determine the average concontration (moles per liter) of acetic acid (CH,COH) present in your vinegar. Record the concentration in Data Table 2 average volume of NaOH (ml) X 1L NaOH 1000 ml NaOH 0,5 mol NaOH 1L NOH...
a-c 5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor)...
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
I MAINLY NEED HELP ON TABLES PLS HELP THANK YOU Materials: NaOH MW = 40 g/mL,...
I MAINLY NEED HELP ON TABLES
PLS HELP THANK YOU
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC2H4O4, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 mL water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the...
Data Table 1 Mass of flask and oxalic acid (g) 117.43 Mass of empty flask (g)...
Data Table 1 Mass of flask and oxalic acid (g) 117.43 Mass of empty flask (g) 116.93 Mass of oxalic acid (g) 0.5 Moles of oxalic acid (mol) Final volume of NaOH (mL) 17 Initial volume of NaOH (mL) 5 Volume of NaOH used (mL) 12 Moles of NaOH (mol) Molarity of NaOH (M) Data Table 2 Mass of flask and vinegar (g) 126.61 Mass of empty flask (g) 121.63 Mass of vinegar (g) 4.98 Final volume of NaOH (mL)...
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted...
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...
A 21.70 mL volume of 0.0940 M NaOH is required to reach the phenolphthalein endpoint in the titration of a 3.06 g sample of vinegar. a. Calculate the number of moles of acetic acid in the vinegar sample. Calculate the mass of acetic acid in the vinegar sample. The molar mass of acetic acid is 60.05 g/mol. b. Calculate the percent by mass of acetic acid in the vinegar sample. Assume the density of the vinegar is 1.00 g/mL. Express...
Uz moi or acetic acid reacts Question 10 (1 point) A student finds that 12.43 milliliters of NaOH solution with a concentration of 0.155 M are needed to neutralize a vinegar sample. How many moles of NaOH were added to the sample? Your Answer: Answer units Question 11 (1 point) A student determines that 0.00170 moles of NaOH were required to neutralize the acetic acid in a sample of vinegar. How many moles of acetic acid must have been present...
9. A 4-gram sample of vinegar containing acetic acid CH3C 0.2 M NaOH. After 15 mL of NaOH was added, the stoichiometric p reached as evidenced by the change in color of the indicator. Calculate percent of acetic acid in the vinegar. Molar mass of acetic acid=60.05 ining acetic acid CH3COOH was titrated with s added, the stoichiometric point was or of the indicator. Calculate the mass
1. A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known mass of KHP was titrated with the NaOH solution until a light pink color appeared using phenolpthalein indicator. Using the volume of NaOH required to neutralize KHP and the number of moles of KHP titrated, the concentration of the NaOH solution was calculated. Molecular formula of Potassium hydrogen phthalate: HKC8H404 Mass of KHP used for standardization (g) 0.5100 Volume of NaOH required to neutralize...
Exercise 1 - Questions 1. The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percent error between your result and the manufacturer statement? Show your work 30 Using the following equation, determine the average concontration (moles per liter) of acetic acid (CH,COH) present in your vinegar. Record the concentration in Data Table 2 average volume of NaOH (ml) X 1L NaOH 1000 ml NaOH 0,5 mol NaOH 1L NOH...
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
I MAINLY NEED HELP ON TABLES
PLS HELP THANK YOU
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC2H4O4, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 mL water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the...
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...
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