Question

A 2011 poll found that 72​% of citizens of a certain country believe that high achieving high school students should be recruited to become teachers. This poll was based on a random sample of 1005 citizens.

1. Find a​ 90% confidence interval for the proportion of citizens who would agree with this. [ ]% - [ ]%? Type integers or decimals rounded to one decimal place as​ needed

Answer 1

Answelt Given that A 2011 poll-found that 70% of citizens of acestain Counter based on a random sample of 1005 citizens. We know the formela for the deqruited contidence interval in při zop whele Å in the population - pea poltion and sp= A (1-6)/n ; nt sample size a in the collesponding ascole. hese Ñ = 0.72 and na 1005. Since confidence level in 90% we have the 2 sede as 1,645 p = 10.72 xord7%awe 2.01013881927 100 5

pl+ 2 rp = 0.7 0 7 010 24764857 =(0.722, 017199.) Thus the ecareided 90% confidence inleevel for the peopolfion of citizens who would agere in (72%, 71.97.) 05