A 2011 poll found that 78% of citizens of a certain country believe that high achieving high school students should be recruited to become teachers. This poll was based on a random sample of 1016 citizens. Complete parts a and b below.
a) Find a 90% confidence interval for the proportion of citizens who would agree with this.
b) Do these data refute a pundit's claim that 2/3 of citizens believe this statement? Explain.
A 2011 poll found that 78% of citizens of a certain country believe that high achieving...
A 2011 poll found that 72% of citizens of a certain country believe that high achieving high school students should be recruited to become teachers. This poll was based on a random sample of 1005 citizens. 1. Find a 90% confidence interval for the proportion of citizens who would agree with this. [ ]% - [ ]%? Type integers or decimals rounded to one decimal place as needed
A particular poll tracks daily the percentage of citizens from a certain country who approve or disapprove of the job the President is doing. Daily results are based on telephone interviews with approximately 1200 national adults. The poll reported that 43% of adults approve of the President doing his job. A media outlet claimed the true proportion to be 44%. Does the poll contradict this claim? Complete parts a through c. Question: Find the 95% confidence interval. Answer: (_________,_________)
A particular poll tracks daily the percentage of citizens from a certain country who approve or disapprove of the job the President is doing. Daily results are based on telephone interviews with approximately 1500 national adults. The poll reported that 43% of adults approve of the President doing his job. A media outlet claimed the true proportion to be 44%. Find the 99% confidence interval _______________, ________________ (round to 3 decimal points) Please show the math and not just the...
please answer all parts Q1 A school found that 78 out of a random sample of 100 students had read a book in a month. (a) Find a 96% confidence interval for the proportion in the corresponding population. (b) The school has decided that a more precise estimate is needed and wishes to reduce the width of the confidence interval by a quarter. How many more students should be investigated if the school wants to find the 96% confidence interval...
According to a health organization in a certain country, 21.8% of the population smoked in 2008. In 2014, a random sample of 650 citizens of this country was selected, 129 of whom smoked. Complete parts a through c below. a. Construct a 90% confidence interval to estimate the actual proportion of people who smoked in this country in 2014. A 90% confidence interval to estimate the actual proportion has a lower limit of nothing and an upper limit of nothing....
A poll found that 61% of a random sample of 1002 adults said that they believe in ghosts. a. Determine the margin of error for a 99% confidence interval. b. Without doing any calculations, indicate whether the margin of error is larger or smaller for a 90% confidence interval.
A Gallup poll found that 493 of 1050 adult Americans believe it is the responsibility of the federal government to make sure all Americans have healthcare coverage. What is the sample in this study? What is the population of interest? What is the variable of interest in this study? Is it qualitative or quantitative? Based on the results of this study, obtain a point estimate for the proportion of adult Americans who believe it is the responsibility of the federal...
A poll found that 53% of a sample of 1170 teens in a certain large country go online several times a day. (Treat this sample as a simple random sample.) Find the margin of error for this poll if we want 90% confidence in our estimate of the percent of teens in the country who go online several times a day. [ ]? - Round to one decimal place as needed
A poll found that 53% of a sample of 1170 teens in a certain large country go online several times a day. (Treat this sample as a simple random sample.) Complete parts a through e below. a) Find the margin of error for this poll if we want 90% confidence in our estimate of the percent of teens in the country who go online several times a day. 24% (Round to one decimal place as needed.) b) Explain what the...
Achieving a high score on the LSAT examination is a prerequisite for getting accepted to law school. A random sample of 15 students from law school 1 had an average LSAT score of 680 with a standard deviation of 84. A random sample of 12 students from law school 2 had an average LSAT score of 634 with a standard deviation of 92. Making appropriate assumptions, find a 90% confidence interval for the difference between mean LSAT scores at these...