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For the reaction below, Kc = 1.10 × 10⁻⁸. What is the equilibrium concentration of OH⁻...

For the reaction below, Kc = 1.10 × 10⁻⁸. What is the equilibrium concentration of OH⁻ if the reaction begins with 0.190 M HONH₂? HONH₂ (aq) + H₂O (l) ⇌ HONH₃⁺ (aq) + OH⁻ (aq)

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HONH be e ut the imihal eoreantrahon Q0.19 (M) Cet He br tae cnuilbbatum aonstantfte scadhion bdoro Re HONHO (aq) oH (ag) HONKe ea2 Ke MIX108 & 9.406 x10-4 019 9.406 x10 4Equitibrtum cenentwahon of o 2 ON JOO.A57 010-4 M) equabbutum eorestreahon Он 4.57 x10(M)

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