An unknown compound contains only C, H, and O. Combustion of 3.20 g of this compound...

Question

Question

Answer 1

Answer #1

44 g CO2 contain 12 g C

6.39 g CO2 contain 6.39 x 12 / 44 = 1.74 g C

% C = (1.74 / 3.20) x 100

% C = 54.37

18 g H2O contain 2 g H

2.62 g H2O contain 2.62 x 2 / 18 = 0.29 g

% H = (0.29 /3.20) x 100

% H = 9.06

% O = 100 - 54.37 - 9.06 = 36.57 %

% element atomic ratio simplest ratio 54.37 / 12 = 4.53 C = 54.37 4.53 /2.28 = 2.0 9.06 / 2.28 = 4.0 9.06 / 1 = 9.06 H = 9.06

Answer 2

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