Question

< Question 1 of 3 > Attempt 2 - An unknown compound contains only C, H, and O. Combustion of 6.60 g of this compound produced 13.2 g CO, and 5.40 g H,O. What is the empirical formula of the unknown compound? Insert subscripts as needed. empirical formula: C,H,O,

Answer 1

co molar massa 44 glmol Ho molar mass = 18 gimol 44 gr co contain 12 gr carbon 13-2 gg co contain= 13-2 412) gr carbon 44 mass of carbon = 3.698. 6.6 gr compound contain 3.69r carbon 100 x 3-6 too gr compound contain 54-54). C' 6.6 1888 to contain ago Hydrogen 5.4 gr to contain= 5.4 x 21 gr Hydrogen mass of Hydrogen = 0.6 gr . 6.688 compound contain of gr Hydrogen 100 gr compound containa 10o xo o 9.00H 6.6 7. Of d'= 100-(4. ob e't % of it) = 100-(54.54+9.09)=36-37% i

step-1 percentage of elements s H 0 54.54 9.09 36-37 step-2 Dividing by the respective atomic weight's 54.54 9.09 36 37 16 12 among Step 4.545 9.09 2.27 : Dividing the values in step-2 Them by the smallest number 4.545 9.09 2.27 2-27 2-27 2.27 2-27 empirical formula = CHO