Question

oghment 11 The Simple Pendulum Simo 10 10 . Why is the simple pendulum frequently used as an example of simple harmonie motion? Pendulum Very close to simple harmonic motion. 9+ the acceleration is proportional to A-Omax. Sinua the negative displacement, the OCCA E PO anguar I S. Pio portond Mas + 2. Given the following data, plot the period is the length, then plot the periods o n the require the square root of the length of angular displacena L 0.150 m 0.200 m 0.250 0.300 m 0.400 m 0.500 0.500 m K T 0 A .78 0.00 1.00 1.000 1.260 1.419 1.555 - VL 0.8 Spring 0.7 period (T) 0.5 1 1.5 Length(cm)

Answer 1

1. The motion of a simple pendulum is very close to Simple Harmonic Motion (SHM). SHM results whenever a restoring force is proportional to the displacement, a relationship often known as Hooke’s Law when applied to springs.

F = -kx

Where F is the restoring force, k is the spring constant, and x is the displacement.

bu = M esoɔbw mg sin o -10.

here, mg sin$\theta$ acts as restoring force which brings the object back to its normal position/mean position making it very close to SHM performance.Only thing to be considered is pendulum oscillates by small angle .

2.3. Time period vs sq. root of Length variation

Period(T) vs Length(L) Period(T in sec) 0.1 0.15 0.2 0.25 03 0.4 0.45 0.5 0.55 0.6 0.35 R Length(L in metres)

Period(1) vs Length (L) Period(T in sec) 0.4 0.45 0.5 0.65 0.7 0.75 0.8 0.55 0.6 sq root of Length (L in metres)

3. plot 2 gave us a straight line as T is directly proportional to $\sqrt{}$ T

4.To get the idea of variation that T is a straight line only in case 2

5.slope = 1.99 , y intercept= 0