Question

please do all parts

A chunk of lead with mass m = 400 g (in air) is found to have an apparent mass ma = 325 g when completely submerged in an unknown liquid. The density of lead is 11.342 g/cm?. a. What mass of fluid, in grams, does the iron displace? b. What is the volume of the chunk of iron? c. What is the unknown fluid's density, in g/cm?

Answer 1

A)

Apparent weight = actual  weight - buoyancy force

Apparent weight = actual  weight -  displaced water water weight

displaced water water weight = actual  weight - Apparent weight

= 400-325 = 75 gm

displaced water mass = 75 g

B) mass of lead = density*volume

volume = mass of lead /density =400 /11.342 =35.2671487 cm³ ans

C)

buoyancy force = rho *volume *g

75 * 9.8 = rho *volume *9.8

volume = 75/volume = 75/(400 /11.342) =2.126625 g/cm³

so density of unknown liquid = 2.126625 g/cm³

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